Question

What is the area of a rectangle whose length is (5x + 2)cm and whose width is (3x + 1)cm?

Answer 1

Answer:

$\displaystyle A = 15x^2 + 11x + 2\text{ cm}^2$

Step-by-step explanation:

We are given that the length and width of a rectangle is given by:

$\ell = (5x + 2)\text{ cm} \text{ and } w = (3x+1)\text{ cm}$

And we want to find the area of the rectangle.

Recall that the area of a rectangle is given by:

$\displaystyle A = w\ell$

Substitute:

$A = (3x+1)(5x+2)$

Expand and simplify:

$\displaystyle \begin{aligned}A &= 5x(3x+1) + 2(3x+1) \\ &= (15x^2+5x)+(6x+2) \\ &= (15x^2)+(5x+6x)+(2) \\ &= 15x^2 + 11x +2 \end{aligned}$

Hence, the area of the rectangle is:

$\displaystyle A = 15x^2 + 11x + 2\text{ cm}^2$