Question

plss helppp!!

pls show how is it done

solve the equation :

x³ = 3x² + 3x - 1

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Answer 1

Answer:

• x³ = 3x² + 3x - 1
• x³-  3x² -  3x + 1 = 0
• (x³ + 1) - 3x(x + 1) = 0
• (x + 1)(x² - x + 1 - 3x) = 0
• (x + 1)(x² - 4x + 1) = 0
• (x + 1)(x² -4x + 4 - 3) = 0
• (x + 1)((x - 2)² - (√3)²) = 0
• (x + 1)(x - 2 + √3)(x - 2 - √3) = 0

• x = -1
• x = 2 - √3
• x = 2 + √3