Answer:
Step-by-step explanation:
14.
by pythagoras,s theorem
[tex]x=\sqrt{2^2+2^2} =\sqrt{8} =\sqrt{4 \times 2} =2\sqrt{2} \\y^2=x^2+2^2=(2\sqrt{2} )^2+2^2=8+4=12=4 \times 3\\y=2\sqrt{3}[/tex]
15.
first perpendicular=y(say)
and second perpendicular=z (say)
y²=9²+7²=81+49=130
z²=y²+5²=130+25=155
x²=z²+4²=155+16=171
x=√(171)