Question

A capacitor consists of a set of two parallel plates of area A separated by a distance d. This capacitor is connected to a battery and charged until its plates carry charges If the separation between the plates is doubled, the electrical energy stored in the capacitor will

Answer 1

Answer:

The electrical energy stored in the capacitor will be cut in half.

Explanation:

The energy in a capacitator is given by E=C$V^{2}$/2 and the formula for the Capacitance in a capacitator is C= $\frac{Q}{V}$ = ε$\frac{A}{d}$ .

So if we replace C = ε$\frac{A}{d}$  in the first equation we have:

E = ε$\frac{AV^{2} }{2d}$