Question

1. A bicycle initially moving with a velocity
5.0 m s-1 accelerates for 5 s at a rate of 2 m s? Wh
will be its final velocity ?
​

Answer 1

Answer:

$\boxed {\boxed {\sf 15 \ m/s \ or \ 15 \ m*s^{-1}}}$

Explanation:

We are asked to find the final velocity. We are given the acceleration, time, and initial velocity, so we can use the following kinematics formula.

$v_f= v_i+ at$

In this formula, $v_f$ is the final velocity, $v_i$ is the initial velocity, $a$ is the acceleration, and $t$ is the time.

The bicycle has an initial velocity of 5.0 m *s⁻¹ or m/s, acceleration of 2 m/s², and a time of 5 seconds.

$\bullet \ v_i = 5.0 \ m/s \\\bullet \ a= 2\ m/s^2\\\bullet \ t= 5 \ s$

Substitute the values into the formula.

$v_f=5.0 \ m/s + ( 2\ m/s^2 * 5 \ s)$

Solve inside the parentheses.

• $\frac {2 \ m}{s^2}* 5 \ s = \frac{ 2 \ m}{s} * 5 = \frac{ 10 \ m}{s} = 10 \ m/s$

$v_f= 5.0 \ m/s + (10 \ m/s)$

Add.

$v_f= 15 \ m/s$

The units can also be written as:

$v_f= 15 \ m*s^{-1}$

The bicycle's final velocity is 15 meters per second.