Question

The volume of a gas was 48 mL when the temperature was 159.6 ºC. If the temperature was initially 4.9 ºC, and there was no change in the pressure, what was the initial volume of the gas?

Answer 1

• V1=48mL
• T1=159.6°C
• T2=4.9°C
• V2=?

According to Charles law

$\boxed{\sf \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}}$

$\\ \sf\longmapsto \dfrac{48}{159.6}=\dfrac{V_2}{4.9}$

$\\ \sf\longmapsto V_2=\dfrac{48\times 4.9}{159.6}$

$\\ \sf\longmapsto V_2=\dfrac{235.2}{159.6}$

$\\ \sf\longmapsto V_2=1.4mL$