Question

I need HELP ASAP!! Please explain how to solve the problem

Answer 1

Answer:

$(x+1)^2+(y+4)^2=9$

Step-by-step explanation:

The general format for the equation of a circle is the following:

$(x-h)^2+(y-k)^2=a^2$

Where $(h,k)$ is the center of the circle and ($a$) is the circle's radius. Please note, that the circle ($(x-h)^2+(y-k)^2=a^2$) has a center that is (h) units to the right of the origin, and (k) units above the origin.

The given circle has a center at $(-1,-4)$, moreover, its radius is (3) units. Therefore, one must substitute these points into the equation of a circle and simplify to find its equation:

$(x-h)^2+(y-k)^2=a^2$

$(x-(-1))^2+(y-(-4))^2=(3)^2$

$(x+1)^2+(y+4)^2=9$

Answer 2

Answer:

Step-by-step explanation: Let's first determine the center of the circle

which is represented by the red dot and it has the coordinates (-1, -4).

The radius of the circle is a segment that joins the center of the

circle to a point on the circle and all radii of a circle are congruent.

The radius of the circle shown here is 3.

Now, the equation of a circle is (x - h)² + (y - k)² = r² where

(h, k) is the center of the circle and r is the radius.

Now we plug all our given information into the formula.

So we have [x - (-1)]² + [y - (-4)]² = (3)².

Notice that I changed the parentheses in the formula to brackets

so that we wouldn't be dealing with too many sets of parentheses.

Changing the brackets back to parentheses,

our equation is (x + 1)² + (y + 4)² = 9.