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Kurt Blixen must invest $85,2296.94.

Given the following data;

  • Interest rate = 4.75%
  • Simple interest = $10,000
  • Time = 90 days

To find how much money Kurt Blixen must invest;

Mathematically, simple interest is given by the formula;

[tex]S.I = \frac{PRT}{100}[/tex]

Where:

  • S.I is the simple interest.
  • P is the principal amount.
  • R is the interest rate.
  • T is the time measured in years.

First of all, we would convert the time in days to years.

Conversion:

365 days = 1 year

90 days = x year

Cross-multiplying, we have;

[tex]365 * x = 90\\\\x = \frac{90}{365}[/tex]

x = 0.247 year

Making P the subject of formula;

[tex]P = \frac{S.I(100)}{RT}[/tex]

Substituting the values into the formula, we have;

[tex]P = \frac{10000(100)}{4.75*0.247}\\\\P = \frac{1000000}{1.1733}[/tex]

P = $85,2296.94

Therefore, Kurt Blixen must invest $85,2296.94.

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