Question

a leaking tap drops water at the rate of 3 drops every second.each drop is approximately 1 ml. how many liters of water will leak from the tap during a day?
a. 5 liters
b. 50 liters
c.500 liters
d.15 liters​

Answer 1

A leaking tap that drops water at the rate of 3 drops every second, will leak 259.2 L in a day.

We know that a leaking tap drops water at the rate of 3 drops every second and that each drop is approximately 1 ml. The milliliters of water dropped every second are:

$\frac{3drop}{1s} \times \frac{1mL}{1drop} = \frac{3mL}{1s}$

We want to know the number of seconds in 1 day. We will use the following conversion factors:

• 1 day = 24 h

• 1 h = 60 min

• 1 min = 60 s

$1day \times \frac{24h}{1day} \times \frac{60min}{1h} \times \frac{60s}{1min} = 86400 s$

3 mL of water are dropped every second. The mL of water dropped in 86400 s are:

$86400 s \times \frac{3mL}{1s} = 259200 mL$

Finally, we will convert mL to L using the conversion factor 1 L = 1000 mL.

$259200 mL \times \frac{1L}{1000 mL} = 259.2 L$

Approximately 259.2 L of water will be dropped in 1 day.

You can learn more about unit conversions here: https://brainly.com/question/19420601