Question

The armature of an AC generator has 200 turns, which are rectangular loops measuring 5 cm by 10 cm. The generator has a sinusoidal voltage output with an amplitude of 18 V. If the magnetic field of the generator is 300 mT, with what frequency does the armature turn

Answer 1

Answer:

$f=9.55Hz$

Explanation:

From the question we are told that:

Number of Turns $N=200$

Length $l=5cm to 10cm$

Voltage $V=18V$

Magnetic field $B=300mT$

Generally, the equation for Frequncy of an amarture is mathematically given by

$f =\frac{ V}{(N B A * 2 pi )}$

$f =\frac{ 18}{(200 300*10^{-3} (10*10^-2)(5*10^{-2}) * 2 *3.142 )}$

$f=9.55Hz$