The coefficient of kinetic friction between a large box and the floor is 0.21. A person pushes
horizontally on the box with a force of 165 N for a distance of 2.8 m. If the mass of the box is
72 kg, what is the total work done on the box? (Round your answer to a whole number)

Respuesta :

DALAU

Answer:

W= 47

Explanation:

Given:

m = 72 kg

F = 165 N along horizontal

s = 2.8 m

\mu = 0.21

The net force acting on the box is

W= 165-(0.21 * 72 * 9.81)) * 2.8

W= 46,68384

W= 47

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