Answer:
one possible value for x is 31/40
Step-by-step explanation:
Let's isolate the 20x term. Add 13 to all three terms:
2 + 13 < 20x - 13 + 13 < 3 + 13
and this simplifies to:
15 < 20x < 16
Dividing all three terms by 20, we get:
15/20 < x < 16/20
A fraction halfway between 15/20 and 16/20 is (31/20)/2, so
one possible value for x is 31/40.
Check by substituting this into the original equation and checking whether that equation is now true:
2 <20(31/40) - 13 < 3
or
2 < 31/2 < 16, or 2 < 15.5 < 16 (this is true, so 31/40 is a solution)
