Which of the following is equal to the rational expression when x ≠ -4 or 16?

Answer:
C
Step-by-step explanation:
Given
[tex]\frac{x^2-16}{(x-16)(x+4)}[/tex]
The numerator is a difference of squares
x² - 16 = (x - 4)(x + 4)
= [tex]\frac{(x-4)(x+4)}{(x-16)(x+4) }[/tex] ← cancel the common factor (x + 4) on numerator/ denominator
= [tex]\frac{x-4}{x-16}[/tex] → C