Respuesta :
Answer:
[tex]h^{-1}[/tex] (t) = [tex]\frac{7-t}{6}[/tex]
Step-by-step explanation:
let y = h(t) and rearrange making t the subject
y = - 6t + 7 ( add 6t to both sides )
6t + y = 7 ( subtract y from both sides )
6t = 7 - y ( divide both sides by 6 )
t = [tex]\frac{7-y}{6}[/tex]
Change y back into terms of x with t = [tex]h^{-1}[/tex] (t)
[tex]h^{-1}[/tex] (t) = [tex]\frac{7-t}{6}[/tex]
