Given OSALE, solve for x.
3
3x + 4
5x-6
S
3
A

Answer:
x=5
Step-by-step explanation:
The sides have to be equal length
3x+4 = 5x-6
Subtract 3x from each side
3x+4-3x = 5x-6-3x
4 = 2x-6
Add 6 to each side
4+6 = 2x-6+6
10 = 2x
Divide by 2
10/2 =2x/2
5 =x
Two parallel sides is 3x + 4 = 5x - 6
[tex]\bf \large \longrightarrow \: \: 3x \: + \: 4 \: = \: 5 x \: - \: 6[/tex]
[tex]\bf \large \longrightarrow \: \:6 \: + \: 4 \: = \: 5x \: - \: 3x[/tex]
[tex]\bf \large \longrightarrow \: \:10 \: = \: 2x[/tex]
[tex]\bf \large \longrightarrow \: \: \frac{10}{2} \: = \: x \\ [/tex]
[tex]\bf \large \longrightarrow \: \: \cancel\frac{10}{2} \: \large \: ^{5} \: = \: x \\ [/tex]
[tex]\bf \large \longrightarrow \: \:x \: = \: 5[/tex]
Option ( B ) is the correct answer.