Question

find the quadratic equations whose roots are 3 and -4
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Answer 1

Answer:

Hello,

Step-by-step explanation:

(x-3)*(x+4)=0 or x²+x-12=0

Answer 2

Answer:

Step-by-step explanation:

$\displyastyle \Large \boldsymbol{} (x-x_1)(x-x_2) \ \ x_1 \ ; \ x_2 -roots \\\\(x-3)(x-(-4))=(x-3)(x+4)=\boxed{x^2+x-12}$