Question

Naina with the weight of 350 N and maina with the weight of 250 N are playing see saw . If Naina is 2m away from the fulcrum find how far must Maina sit in order to balance Naina​

Answer 1

Maina must sit 2.8 meters from the fulcrum in order to balance Naina​.

Given the following data;

• Naina's weight, Nw = 350 N

• Maina's weight, Mw = 250 N

• Naina's distance from fulcrum, Nd = 2 meters

To find how far Maina must sit from the fulcrum in order to balance Naina​;

• Let Maina's distance from the fulcrum be Md.

By balancing a torque;

$N_{w} * N_{d} = M_{w} * M_{d}$

Substituting the values into the formula, we have;

$350 * 2 = 250 * M_{d}\\\\700 = 250 * M_{d}\\\\M_{d} = \frac{700}{250}$

Md = 2.8 meters

Therefore, Maina must sit 2.8 meters from the fulcrum in order to balance Naina​.

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