Neither statement 1, nor statement 2 are correct
The given Stephon's statements are;
Statement 1; [tex]\mathbf{\lim \limits _{x \to -3} f(x)} \ \mathbf{Exist} \ and \mathbf{\lim \limits _{x \to -3} f(x) = 1}[/tex]
Statement 2; [tex]\mathbf{\lim \limits _{x \to 1} f(x)} \ \mathbf{Exist} \ and \mathbf{\lim \limits _{x \to 1} f(x) = 1}[/tex]
The analysis of the graph and reason for the answer
From the graphed line on the left of the y-axis, we have an open circle at x = -3, and an arrow at the other end pointing towards negative infinity, (-∞) which indicates that the domain is -∞ ≤ x < -3, therefore, at x = -3, f(x) does not exist, therefore, we can write the following statement
The limits of the domain and range of the graph includes;
[tex]\mathbf{\lim \limits _{x \to -3} f(x)} = \mathbf{Does \ not \ exist}[/tex]
f(x) = Defined for -∞ ≤ x < -3
Similarly, from the graphed line on the right of the y-axis, we have an open circle at x = 1 and an arrow at the other end of the line f(x) = 4 pointing towards positive (+∞) infinity, which indicates the domain and the graph of the function is 1 < x ≤ ∞ , therefore, f(x) does not exist at x = 1, and we can write
[tex]\mathbf{\lim \limits _{x \to 1} f(x)} = \mathbf{Does \ not \ exist}[/tex]
From we above, we have that neither statement 1, nor statement 2 are correct
Learn more about open and closed circles on graph lines
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