Answer:
1250 supermarkets
Step-by-step explanation:
Given
[tex]\frac{dN}{dt} = N(1 - 0.0008N)[/tex]
[tex]N(0) = 1[/tex]
Required
Number of supermarkets over a long period of time
To do this, we simply set
[tex]\frac{dN}{dt} = 0[/tex]
So, we have:
[tex]N(1 - 0.0008N) = 0[/tex]
Split
[tex]N = 0\ or\ 1 - 0.0008N = 0[/tex]
Solve: [tex]1 - 0.0008N = 0[/tex]
Collect like terms
[tex]0.0008N = 1[/tex]
Make N the subject
[tex]N = \frac{1}{0.0008}[/tex]
[tex]N = 1250[/tex]
So:
[tex]\lim_{t \to \infty} N(t) = 1250[/tex]