Question

A 1.5kg block slides along a frictionless surface at 1.3m/s . A second block, sliding at a faster 4.3m/s , collides with the first from behind and sticks to it. The final velocity of the combined blocks is 2.0m/s . What was the mass of the second block?

Answer 1

Answer:

The mass of the second block=0.457 kg

Explanation:

We are given that

m1=1.5 kg

v1=1.3m/s

v2=4.3 m/s

V=2.0 m/s

We have to find the mass of the second block.

$m_1v_1+m_2v_2=(m_1+m_2)V$

Let m2=m

Substitute the values

$1.5(1.3)+m(4.3)=(1.5+m)(2)$

$1.95+4.3m=3+2m$

$4.3m-2m=3-1.95$

$2.3m=1.05$

$m=\frac{1.05}{2.3}$

$m=0.457 kg$

Hence,  the mass of the second block=0.457 kg