Answer:
[tex]x = \frac{-(-2) \± \sqrt{(-2)^2 - 4*1*-3}}{2*1}[/tex]
Step-by-step explanation:
Given
[tex]0 = x^2 - 2x -3[/tex]
Required
The correct quadratic formula for the above
A quadratic equation is represented as:
[tex]ax^2 + bx + c = 0[/tex]
And the formula is:
[tex]x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]
So, we have:
[tex]0 = x^2 - 2x -3[/tex]
Rewrite as:
[tex]x^2 - 2x - 3 = 0[/tex]
By comparison:
[tex]a= 1; b = -2; c = -3[/tex]
So, we have:
[tex]x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]
[tex]x = \frac{-(-2) \± \sqrt{(-2)^2 - 4*1*-3}}{2*1}[/tex]