Can anyone help me with this please

Hi there!
[tex]\large\boxed{\frac{1}{4}, -\frac{3}{2}}[/tex]
13y² + 10y - 3 = 5y²
Begin by moving all terms to one side:
13y² + 10y - 3 - 5y² = 0
Combine like terms:
8y² + 10y - 3 = 0
Factor using the guess-and-check method.
(4y - 1)(2y + 3) = 0
Set each factor equal to 0 to find the solutions:
4y - 1 = 0
4y = 1
y = 1/4
2y + 3 = 0
2y = -3
y = -3/2