omaimawaqar225 omaimawaqar225
  • 29-07-2021
  • Mathematics
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Calculate 6+9i/-1+4i

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LammettHash
LammettHash LammettHash
  • 29-07-2021

Multiply the numerator and denominator by the conjugate of the denominator:

[tex]\dfrac{6+9i}{-1+4i} \times \dfrac{-1-4i}{-1-4i} = \dfrac{(6+9i)(-1-4i)}{(-1)^2-(4i)^2}[/tex]

Simplify:

[tex]\dfrac{(6+9i)(-1-4i)}{(-1)^2-(4i)^2} = \dfrac{-6-9i-24i-36i^2}{1-16i^2} = \dfrac{-6-33i-36i^2}{1-16i^2} = \dfrac{-6-33i+36}{1+16} = \boxed{\dfrac{30-33i}{17}}[/tex]

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