Identify the recursive formula for the sequence –3, 9, –27, 81, . . . .




Answer:
Hello,
Answer A
Step-by-step explanation:
[tex]a_n=(-3)*a_{n-1}\\a_1=-3\\Answer\ A[/tex]
Option A is correct -
[tex]f(n)=\left \{ {{f(1)=-3} \atop {f(n)=-3f(n-1)\;\;n > 1}} \right.[/tex]
We have a sequence : –3, 9, –27, 81, . . . .
We have to find the recursive formula for this sequence.
The formula to find the recursive of geometric sequence is -
[tex]a_{n} =ra_{n-1} \;\;\;\;for\;n\geq 2[/tex]
We have the following sequence -
–3, 9, –27, 81, . . . .
First let's see if it is a geometric sequence or not. For a sequence to be a geometric sequence -
[tex]\frac{9}{-3} =\frac{-27}{9} =\frac{81}{-27}= -3=r[/tex]
Hence, it is a geometric sequence with r = -3.
Substituting the value of r in the formula of recursive, we get -
[tex]a_{n} = -3a_{n-1}[/tex] and [tex]a(1)=-3[/tex]
Hence, Option A is correct.
To solve more questions on finding the recursive of a sequence, visit the link below -
brainly.com/question/24506976
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