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caylus

Answer:

Hello,

Answer A

Step-by-step explanation:

[tex]a_n=(-3)*a_{n-1}\\a_1=-3\\Answer\ A[/tex]

Option A is correct -

[tex]f(n)=\left \{ {{f(1)=-3} \atop {f(n)=-3f(n-1)\;\;n > 1}} \right.[/tex]

We have a sequence : –3, 9, –27, 81, . . . .

We have to find the recursive formula for this sequence.

What is the formula to find the recursive of a Geometric sequence?

The formula to find the recursive of geometric sequence is -

[tex]a_{n} =ra_{n-1} \;\;\;\;for\;n\geq 2[/tex]

We have the following sequence -

–3, 9, –27, 81, . . . .

First let's see if it is a geometric sequence or not. For a sequence to be a geometric sequence -

[tex]\frac{9}{-3} =\frac{-27}{9} =\frac{81}{-27}= -3=r[/tex]

Hence, it is a geometric sequence with r = -3.

Substituting the value of r in the formula of recursive, we get -

[tex]a_{n} = -3a_{n-1}[/tex]    and      [tex]a(1)=-3[/tex]

Hence, Option A is correct.

To solve more questions on finding the recursive of a sequence, visit the link below -

brainly.com/question/24506976

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