Question

The heat required to raise 3 kg of copper from 0°C to 10°C raises 1kg of lead from 10°C to 100°C. If the specific heat capacity of copper is 0.095 cal/g°C,find the specific heat capacity of lead.​

Answer 1

The specific heat capacity of lead has been determined to be 0.032 cal/g°C.

The specific heat capacity of a substance is the amount of heat required to increase the temperature of its unit mass by 1 Kelvin rise in temperature.  There is no phase change during the process. This can be expressed as:

Q = mcT

c = $\frac{Q}{mT}$

Where c is the specific heat capacity of the substance, Q is the quantity of heat required, m is the mass of the substance and T is its change in temperature.

In the given question, the heat emitted by the copper mass would be absorbed by the lead mass.

So that;

heat emitted by copper = heat absorbed by lead

$m_{c}$ $c_{c}$($T_{2}$ - $T_{1}$) = $m_{l}$$c_{l}$($T_{2}$ - $T_{1}$)

With the given information in the question, the above equation is expressed as:

3 * 0.095 * (10 - 0) = 1 * $c_{l}$* (100 - 10)

3*0.095*10 = $c_{l}$ * 90

2.85 = $c_{l}$*90

$c_{l}$ = $\frac{2.85}{90}$

  = 0.031667

$c_{l}$ = 0.032 cal/g°C

Therefore, the specific heat capacity of lead is 0.032 cal/g°C.

For more clarifications, visit: https://brainly.com/question/22991121