Respuesta :

Step-by-step explanation:

We know that if (h,k) is the center of any circle and whose radius is = r then its equation is :

[tex] {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} [/tex]

Given, the equation of circle

[tex] {(x + 2)}^{2} + (y - 3) ^{2} = 25 = {5}^{2} [/tex]

By comparing, we will get,

h = -2

k = 3

So, center of the circle is ( -2,3)

[tex]\large \green{ \: \: \: \: \boxed{\boxed{\begin{array}{cc} \bf\:Mark\\\bf\:me\:as\\\bf brainliest \end{array}}}} \\ [/tex]

Answer:

-2;3

Step-by-step explanation:

we have a formular

(x-a)^2 +(y-b)^2=c

the center of the cirlce is (a;b)

so in this case it's (-2;3)

ACCESS MORE
EDU ACCESS
Universidad de Mexico