Respuesta :
Step-by-step explanation:
We know that if (h,k) is the center of any circle and whose radius is = r then its equation is :
[tex] {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} [/tex]
Given, the equation of circle
[tex] {(x + 2)}^{2} + (y - 3) ^{2} = 25 = {5}^{2} [/tex]
By comparing, we will get,
h = -2
k = 3
So, center of the circle is ( -2,3)
[tex]\large \green{ \: \: \: \: \boxed{\boxed{\begin{array}{cc} \bf\:Mark\\\bf\:me\:as\\\bf brainliest \end{array}}}} \\ [/tex]
Answer:
-2;3
Step-by-step explanation:
we have a formular
(x-a)^2 +(y-b)^2=c
the center of the cirlce is (a;b)
so in this case it's (-2;3)