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Answer:
d. End product is that product with a ketone and carboxylic acid.
Explanation:
[tex]{ \sf{NaBH_{4} : }}[/tex]
Sodium borohydride is a reducing agent, it reduces the ketone to a primary alcohol.
[tex]{ \sf{H _{2} O \: and \: H {}^{ + } }}[/tex]
Then acidified water is an oxidising mixture which reverses the reduction reaction.