Find the lateral area of this square
based pyramid.
10 in
Sin
[ ? Jin?

Perimeter:-4a
[tex]\\ \large\sf\longmapsto 4(5)=20in[/tex]
[tex]\boxed{\sf LSA=Height\times Perimeter}[/tex]
[tex]\\ \large\sf\longmapsto LSA=10\times 20[/tex]
[tex]\\ \large\sf\longmapsto LSA=200in^2[/tex]