Question

Evaluate the expression for x = 3 and y= 4.

Answer 1

• x=3
• y=4

$\\ \large\sf\longmapsto -\dfrac{4x^3}{3y^2}$

$\\ \large\sf\longmapsto -\dfrac{4(3)^3}{3(4)^2}$

$\\ \large\sf\longmapsto -\dfrac{4(27)}{3(16)}$

$\\ \large\sf\longmapsto -\dfrac{108}{48}$

$\\ \large\sf\longmapsto -\dfrac{9}{4}$

Answer 2

Answer:

O C) - 9/4

Step-by-step explanation:

- 4x^3/3y^2 where x = 3 and y = 4

Substitute x for 3 and y for 4

- 4(3)^3/3(4)^2

Simplify the exponents

- 4(27)/3(16)

Multiply

- 108/48

Simplify

- 9/4