The cosine of the acute angles are 0.80 and 0.60 respectively
The given parameters are:
[tex]Leg\ 1 = 4x[/tex]
[tex]Leg\ 2 = 3x[/tex]
[tex]Hypotenuse = 5x[/tex]
Let the acute angles be [tex]\alpha[/tex] and [tex]\beta[/tex]
The cosine of the acute angles is calculated using:
[tex]\cos(\alpha) = \frac{Leg\ 1}{Hypotenuse}[/tex]
[tex]\cos(\beta) = \frac{Leg\ 2}{Hypotenuse}[/tex]
So, the formula becomes
[tex]\cos(\alpha) = \frac{4x}{5x}[/tex]
[tex]\cos(\alpha) = \frac{4}{5}[/tex]
[tex]\cos(\alpha) = 0.80[/tex]
and
[tex]\cos(\beta) = \frac{3x}{5x}[/tex]
[tex]\cos(\beta) = \frac{3}{5}[/tex]
[tex]\cos(\beta) = 0.60[/tex]
Hence, the cosine of the acute angles are 0.80 and 0.60 respectively
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