Solution :
Given data :
Total number compressors in a batch = 15 compressors
Number of samples to be tested = 5
Let the number of faulty compressors out of 15 compressors = 2
a) Therefore, the ways of selecting [tex]1[/tex] faulty and [tex]4[/tex] good compressor is
[tex]$=^2C_1 \times ^{13} C_4$[/tex]
The total number of ways = [tex]$^{15}C_5$[/tex]
Therefore, the probability is
[tex]$=^2C_1 \times ^{13}C_4 \times ^{15} C_5$[/tex]
[tex]=0.4761[/tex]
b). Number of ways for selecting [tex]2[/tex] faulty and [tex]3[/tex] good compressor is
[tex]$^{13}C_3[/tex]
Thus the probability
[tex]$=\frac{^{13}C_3}{^{15}C_5}$[/tex]
[tex]$=0.0952$[/tex]