If A is the center of the circle, then which statement explains how segment GH is related to segment FH? Circle A with inscribed triangle EFG; point D is on segment EF, point H is on segment GF, segments DA and HA are congruent, and angles EDA and GHA are right angles.

I can say for sure that the answer is not segment GH ≅ segment FH because the tangents that create the segment FG share a common endpoint. I believe the answer is segment GH ≅ segment FH because arc EF ≅ arc GF.

Step-by-step explanation:

Again, I'm not sure about the correct answer but I know for sure it isn't segment GH ≅ segment FH because the tangents that create the segment FG share a common endpoint.

shubhamchouhanvrVT shubhamchouhanvrVT · Answer 2 · 2022-04-27T09:47:35+02:00

The segment GH and the segment FH are equal to each other because the line AH is coming from the center of the circle and is bisecting the line GF.

What is a circumscribed circle?

The circumcenter of a triangle can be constructed by drawing any two of the three perpendicular bisectors. For three non-collinear points, these two lines cannot be parallel, and the circumcenter is the point where they cross.

Any point on the bisector is equidistant from the two points that it bisects, from which it follows that this point, on both bisectors, is equidistant from all three triangle vertices

Hence the segment GH and the segment FH are equal to each other because the line AH is coming from the center of the circle and is bisecting the line GF.

To know more about a Circumscibed circle follow

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