Answer:
(E) [tex]y=x+3[/tex]
Step-by-step explanation:
Hi there!
Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis).
1) Determine the slope (m)
[tex]m=\displaystyle \frac{y_2-y_1}{x_2-x_1}[/tex] where two points that fall on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Plug in the given points (-4,-1) and ( -1,2):
[tex]m=\displaystyle \frac{2-(-1)}{(-1)-(-4)}\\\\m=\displaystyle \frac{2+1}{-1+4}\\\\m=\displaystyle \frac{3}{3}\\\\m=1[/tex]
Therefore, the slope of the line is 1. Plug this into [tex]y=mx+b[/tex]:
[tex]y=1x+b\\y=x+b[/tex]
2) Determine the y-intercept (b)
[tex]y=x+b[/tex]
Plug in one of the given points and solve for b:
[tex]2=-1+b\\2+1=b\\3=b[/tex]
Therefore, the y-intercept of the line is 3. Plug this back into the original equation:
[tex]y=x+3[/tex]
I hope this helps!