Answer:
[tex]\text{C. }21.39\:\mathrm{units^2}[/tex]
Step-by-step explanation:
The area of a triangle with sides [tex]a[/tex] and [tex]b[/tex] and angle [tex]\gamma[/tex] between them is given by [tex]A=\frac{1}{2}ab\sin \gamma[/tex].
Therefore, in the given triangle, we want to find two sides with the angle between them given. In this case, the angle between the two sides 7.39 and 9.75 is marked as [tex]36.43^{\circ}[/tex]. Assign values:
- [tex]a\implies 7.39[/tex]
- [tex]b\implies 9.75[/tex]
- [tex]\gamma \implies 36.43^{\circ}[/tex]
Substituting these values into our area formula, we get:
[tex]A=\frac{1}{2}\cdot 7.39\cdot 9.75\cdot \sin (36.43)^{\circ},\\A=21.3938371858,\\A\approx \boxed{21.39\:\mathrm{units^2}}[/tex]