The distance between the intercepts of both lines is 2 units
The equation of a line in slope intercept form is:
[tex]y = mx + b[/tex]
Where:
[tex]m \to[/tex] slope
[tex]b \to[/tex] y intercept
For the first line, we have:
[tex]m_1 = 3[/tex] ---- the slope
So, the equation of the first line is:
[tex]y = 3x + b_1[/tex]
For the second line, we have:
[tex]m_2 = 5[/tex] --- the slope
So, the equation of the second line is:
[tex]y = 5x + b_2[/tex]
Both lines intersect at (10,15) means that (10,15) is a common solution to the equation of both lines
i.e.
[tex](x,y) = (10,15)[/tex]
Substitute these values in the first equation and solve for b
[tex]y = 3x + b_1[/tex]
[tex]15 = 3*10 + b_1[/tex]
[tex]15 = 30 + b_1[/tex]
[tex]b_1 = 15 - 30[/tex]
[tex]b_1 = -15[/tex]
So, the equation of the first line is
[tex]y = 3x - 15[/tex]
Repeat the same process for the second line
[tex]y = 5x + b_2[/tex]
[tex]15 = 5*10 + b_2[/tex]
[tex]15 = 50 + b_2[/tex]
[tex]b_2 = 15 - 50[/tex]
[tex]b_2 = -35[/tex]
So, the equation of the second line is
[tex]y =5x - 35[/tex]
The x intercept is when [tex]y =0[/tex]
So, we substitute 0 for y and solve for x in the equations of both lines
For line 1
[tex]y = 3x - 15[/tex]
[tex]0 = 3x - 15[/tex]
[tex]3x= 15[/tex] ---- Collect like terms
[tex]x = 5[/tex] --- Divide both sides by 3
The x intercept of line 1 is 5
For line 2
[tex]y =5x - 35[/tex]
[tex]0 = 5x - 35[/tex]
[tex]5x = 35[/tex] --- Collect like terms
[tex]x = 7[/tex] -- Divide both sides by 5
The x intercept of line 2 is 7
The distance (d) between both is the difference in the intercepts:
[tex]d = 7 - 5[/tex]
[tex]d = 2[/tex]
Read more about intercepts at:
https://brainly.com/question/12791065
