Answer:
1/9
Step-by-step explanation:
The vertex form is
y =a(x-h)^2 +k where (h,k) is the vertex
The vertex is (-2,-3)
y =a(x--2)^2 +-3
y =a(x+2)^2 -3
Substitute the point into the equation
-2 = a(-5+2)^2 -3
-2=a(-3)^2-3
Add 3 to each side
-2+3 = a(9)
1 = 9a
1/9 =a
y =1/9(x+2)^2 -3
The coefficient of the x^2 is 1/9
Answer:
[tex]\frac{1}{9}[/tex]
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k ) = (- 2, - 3) , then
y = a(x + 2)² - 3
To find a substitute (- 5, - 2 ) into the equation
- 2 = a(- 5 + 3)² - 3 ( add 3 to both sides )
1 = a(- 3)² = 9a ( divide both sides by 9 )
[tex]\frac{1}{9}[/tex] = a
y = [tex]\frac{1}{9}[/tex] (x + 2)² - 3
The coefficient of the x² term is therefore [tex]\frac{1}{9}[/tex]
