Respuesta :
Answer:
15050
Step-by-step explanation:
Hello!
So basically, this arithmetic sequence follows the rule (3n-1). What you are looking for is the summation of (3n-1) with a lower limit of 1 and an upper limit of 100. This, plugging it into a calculator (etc. symbolab) or even calculating it manually, we get ∑↑100↓n=1⇒3n-1=15050.
Answer:
S₁₀₀ = 15050
Step-by-step explanation:
There is a common difference between consecutive terms
5 - 2 = 8 - 5 = 3
This indicates the sequence is arithmetic with sum to n terms
[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] [ 2a₁ + (n - 1)d ]
where a₁ is the first term and d the common difference
Here a₁ = 2 and d = 3 , then
S₁₀₀ = [tex]\frac{100}{2}[/tex] [ (2 × 2) + (99 × 3) ]
= 50 (4 + 297)
= 50 × 301
= 15050