Respuesta :

Answer:

15050

Step-by-step explanation:

Hello!

So basically, this arithmetic sequence follows the rule (3n-1). What you are looking for is the summation of (3n-1) with a lower limit of 1 and an upper limit of 100. This, plugging it into a calculator (etc. symbolab) or even calculating it manually, we get ∑↑100↓n=1⇒3n-1=15050.

Answer:

S₁₀₀ = 15050

Step-by-step explanation:

There is a common difference between consecutive terms

5 - 2 = 8 - 5 = 3

This indicates the sequence is arithmetic with sum to n terms

[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] [ 2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Here a₁ = 2 and d = 3 , then

S₁₀₀ = [tex]\frac{100}{2}[/tex] [ (2 × 2) + (99 × 3) ]

       = 50 (4 + 297)

       = 50 × 301

       = 15050

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