Question

Find f such that f'(x) = 8x – 3. f(4) = 0​

Answer 1

Answer: y=29 / (4,29)

Step-by-step explanation:

By graphing $f(x)=8x-3$ and $f(4)=0$ on Desmos. You'll be able to find that when x is 4, y is 29.

Similarly, you can plugin 4 into the original equation ($f(x)=8x-3$) Which looks like:

$8(4)-3\\32-3=29$

Additionally, you can change $f(x)=$ to $y=$ as it is the exact same thing. With that in mind, you can do the same with $f(x)=0$ and just change it to x=4. As you're wanting to know what the y-value is when x=4.

Answer 2

Answer:

4x²-3x+c is our original equation

Step-by-step explanation:

we have an independent number I called this number c

put 4 from x and try to find c

f(4)=4*(4²)-3*(4)+c=0

we have to be careful about f(4) is 0

64-12+c=0 and c is -52 so our original equation is 4x²-3x-52