Answer:
The right solution is "-602.69 KJ heat".
Explanation:
According to the question,
The 100.0 g of carbon dioxide:
= [tex]\frac{100.0 \ g}{114.33\ g/mole}[/tex]
= [tex]0.8747 \ moles[/tex]
We know that 16 moles of [tex]CO_2[/tex] formation associates with -11018 kJ of heat, then
0.8747 moles [tex]CO_2[/tex] formation associates with,
= [tex]-\frac{0.8747}{16}\times 11018 \ KJ \ of \ heat[/tex]
= [tex]-0.0547\times 11018[/tex]
= [tex]-602.69 \ KJ \ heat[/tex]
