Respuesta :
Answer:
a) 0.18 = 18% probability a randomly chosen business customer flying with Global is on a jumbo jet.
b) 0.3 = 30% probability a randomly chosen non-business customer flying with Global is on an ordinary jet.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
Question a:
Event A: Jumbo
Event B: Business
60% of its capacity is provided on jumbo jets.
This means that [tex]P(A) = 0.6[/tex]
On jumbo jets, 30% of the passengers are on business
This means that [tex]P(B|A) = 0.3[/tex]
Desired probability:
We want to find [tex]P(A \cap B)[/tex], so:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
[tex]P(A \cap B) = P(B|A)P(A) = 0.6*0.3 = 0.18[/tex]
0.18 = 18% probability a randomly chosen business customer flying with Global is on a jumbo jet.
b) What is the probability a randomly chosen non-business customer flying with Global is on an ordinary jet?
Event A: Ordinary
Event B: Non-business
60% of its capacity is provided on jumbo jets.
So 100 - 60 = 40% are ordinary, which means that [tex]P(A) = 0.4[/tex]
On ordinary jets 25% of the passengers are on business.
So 100 - 25 = 75% are non-business, that is [tex]P(B|A) = 0.75[/tex]
Desired probability:
We want to find [tex]P(A \cap B)[/tex], so:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
[tex]P(A \cap B) = P(B|A)P(A) = 0.75*0.4 = 0.3[/tex]
0.3 = 30% probability a randomly chosen non-business customer flying with Global is on an ordinary jet.
