Question

A line passes through (-6,-5) and has the slope of 2/3

HELPPPP PLEASE!!

Answer 1

Answer:

y = 2/3x-1

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b  where m is the slope and b is the y intercept

y = 2/3x +b

Using the point (-6,-5)

-5 = 2/3(-6)+b

-5 = -4 +b

Add 4 to each side

-5+4 = b

-1 =b

y = 2/3x-1

Answer 2

Answer:

$y = \frac{2}{3}x - 1$

Step-by-step explanation:

$y = mx + c \\ \\ m = slope \\ c = y \: \: intercrept$

$m = \frac{2}{3}$

$y = mx + c \\ - 5 = \frac{2}{3} \times - 6 + c \\ - 5 = \frac{ - 12}{3} + c \\ - 5 = - 4 + c \\ - 5 + 4 = c \\ - 1 = c$

So, the equation of the line is,

$y = mx + c \\ y = \frac{2}{3}x - 1$