karlalopezv56j karlalopezv56j
  • 27-07-2021
  • Mathematics
contestada

In a sequence, the first term is 6 and the common difference is 4. The thirtieth (30th) term of
this sequence is
1) 118
2) 122
3) 1261
4) 130

Respuesta :

ahvi31 ahvi31
  • 27-07-2021
If the first term is 6, there are 29 terms left until the 30th term so you do 29 x 4 = 116 then do 6 + 116 = 122
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