Question

calculate the maximum mass of ethanol that could be obtained from 30.0g of glucose​

Answer 1

Answer:

15.3g

Explanation:

C6H12O6 → 2C2H5OH + 2CO2

1 mol C6H12O6 = 180g

1 mol CH3-CH2-OH = 46g

From 180g glucose ethanol can get = 92g

30g glucose ethanol gives us = (92*30)/180 = 15.33g