Answer:
1/ab en (c/be^-x+c)
Step-by-step explanation:
Sure is a harsh question! Here's my Explanation
b+ce^x = t
ce^x an = dt
e^xan = dt/c
an = dt/ce^x = dt/c(t-b/c) = at/(t-b)
en = t-b/c
A/b+ce^x dx = a/t dt/t-b
a ∫1/t (t-b) dt = 1/a∫ (1/(t-b) - 1/t) dt
= 1/ab [∫1/(t-b) dt + ∫-1/t dt]
= 1/ab [en (t-b) - en(t)]
= 1/ab en ((t-b)/t)
t = b + ce^x
= 1/ab en (b+ce^x -b/b+ce^x)
=1/ab en (ce^x/b+ce^x)
= 1/ab en (c/be^-x+c)
