Question

please help solve for y!

Answer 1

As both angles are supplementary

$\\ \Large\sf\longmapsto 3x+(2x+3y)=180°$

$\\ \Large\sf\longmapsto 3x+2x+3y=180$

$\\ \Large\sf\longmapsto 5x+3y=180$

$\\ \Large\sf\longmapsto 3y=180-5x$

$\\ \Large\sf\longmapsto y=\dfrac{180-5x}{3}$

And

$\\ \Large\sf\longmapsto 3x=90$

$\\ \Large\sf\longmapsto x=\dfrac{90}{3}$

$\\ \Large\sf\longmapsto x=30$

Now

• Putting value

$\\ \Large\sf\longmapsto y=\dfrac{180-5x}{3}$

$\\ \Large\sf\longmapsto y=\dfrac{180-5(30)}{3}$

$\\ \Large\sf\longmapsto y=\dfrac{180-150}{3}$

$\\ \Large\sf\longmapsto y=\dfrac{30}{3}$

$\\ \Large\sf\longmapsto y=10$