Question

What is the value of the capacitance of a capacitor that stores 40
μ
C on each plate, when a potential difference of 10 V is applied to it?

Answer 1

• Charge=Q=40uC
• Potential difference=V=10V
• Capacitance=C=?

We know

$\boxed{\sf Q=CV}$

$\\ \large\sf\longmapsto C=\dfrac{Q}{V}$

$\\ \large\sf\longmapsto C=\dfrac{40}{10}$

$\\ \large\sf\longmapsto C=4\mu F$