Question

A wire, 0.60 m in length, is carrying a current of 2.0 A and is placed at a certain angle with respect to the magnetic field of strength 0.30 T. If the wire experiences a force of 0.18 N, what angle does the wire make with respect to the magnetic field

Answer 1

Answer:

$\theta=30 \textdegree$

Explanation:

From the question we are told that:

Current $I=2.0A$

Length $L=0.60m$

Magnetic field $B=0.30T$

Force $F=0.18N$

Generally the equation for Force is mathematically given by

$F = BIL sin\theta$

$sin\theta=\frac{F}{BIL}$

$\theta=sin^{-1}\frac{0.18}{0.3*2*0.6}$

$\theta=30 \textdegree$