Question

Glycogen phosphorylase (GP) targets the non-reducing ends of glycogen to cleave glycogen and produce one glucose-1P at a time. GP will do this until it is three glucose molecules from the glucose molecule with the branch point - at which time another enzyme takes over the degradation. Which glucose molecule(s) on glycogen are substrates for GP based on this information

Answer 1

Answer:

Glucose molecules bound together by a-1,4 glycosidic linkages, and they must be >4 glucose molecules away from a branch point.

Explanation:

Glycogen phosphorylase can not degrade the glucose polymer close to the branch point because these sections of the glycogen molecule are to short for the glucose polymer to fit properly into the active site of the GP enzyme. The GP enzyme can therefore only degrade the 'straight' portions of glycogen. To degrade a branch point, a debranching enzyme is required. The debranching enzyme has transferase (cleaves off glucose molecules right before branch point and moves them to the end of another branch) and a-1,6 glycosidic activity which removes the branching glucose.

Answer 2

Glucose molecules are restrained together by a-1,4 glycosidic connections, and they must be >4 glucose molecules missing from a branch issue.

What are Glucose molecules?

Glycogen phosphorylase can not devalue the glucose polymer proximate to the branch pinpoint because these provinces of the glycogen molecule are too quick for the glucose polymer to fit properly into the involved site of the GP enzyme.

The GP enzyme can thus, only impair the 'straight' pieces of glycogen. To degrade a branch point, a debranching enzyme is directed.

The debranching enzyme has transferase (cleaves off glucose molecules correct before the attachment point and carries them to the end of another branch) and a-1,6 glycosidic movement which dismisses the branching glucose.

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