Answer:
Step-by-step explanation:
From the given angles ∠ABC and ∠GHK,
m∠ABC = m∠GHK [Given]
m∠ABC = m∠GHL + m∠KHL [Since, ∠GHL + ∠KHL = ∠GHK]
(6x + 2)° = (5x - 27)° + (3x + 1)°
6x + 2 = 8x - 26
8x - 6x = 28
2x = 28
x = 14
m(BC) = m(HK) [Given]
3z + 6 = 8z - 9
8z - 3z = 6 + 9
5z = 15
z = 3
m(AB) = m(GH)
5y - 8 = 3y
2y = 8
y = 4
m∠ABC = mGHK = (6x + 2)
= 6(14) + 2
= 86°
m(AB) = m(GH) = 3y
= 3(4)
= 12 units
m(BC) = m(HK) = (3z + 6)
= 3(3) + 6
= 15 units
m(∠KHL) = (3x + 1)°
= 3(14) + 1
= 43°
