Answer:
The answer is "[tex]\bold{\Delta LAW \cong \Delta WKL}[/tex]. By applying the ASA congruence postulate rule".
Step-by-step explanation:
[tex]\Delta LAW\ and\ \Delta WKL\\\\AW\perp WL\ and \ WL\perp KL\\\\\angle AWL = \angle WLK .......[each \ 90^{\circ}]\\\\WL=WL.......\ [Reflexive \ property]\\\\\angle ALW = \angle KWL........\text{give in picture}\\\\[/tex]
[tex]\therefore,[/tex] by ASA postulate of congruence
[tex]\Delta LAW \cong \Delta WKL\\\\[/tex]
The ASA postulate states that when two angles on the included side with one triangle were congruent to two angles on the included side of the second triangle, then the triangles are said to have been congruent.